3.80 \(\int \frac{A+B x^2}{(a+b x^2)^2} \, dx\)

Optimal. Leaf size=63 \[ \frac{(a B+A b) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{2 a^{3/2} b^{3/2}}+\frac{x (A b-a B)}{2 a b \left (a+b x^2\right )} \]

[Out]

((A*b - a*B)*x)/(2*a*b*(a + b*x^2)) + ((A*b + a*B)*ArcTan[(Sqrt[b]*x)/Sqrt[a]])/(2*a^(3/2)*b^(3/2))

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Rubi [A]  time = 0.0220863, antiderivative size = 63, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.118, Rules used = {385, 205} \[ \frac{(a B+A b) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{2 a^{3/2} b^{3/2}}+\frac{x (A b-a B)}{2 a b \left (a+b x^2\right )} \]

Antiderivative was successfully verified.

[In]

Int[(A + B*x^2)/(a + b*x^2)^2,x]

[Out]

((A*b - a*B)*x)/(2*a*b*(a + b*x^2)) + ((A*b + a*B)*ArcTan[(Sqrt[b]*x)/Sqrt[a]])/(2*a^(3/2)*b^(3/2))

Rule 385

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> -Simp[((b*c - a*d)*x*(a + b*x^n)^(p +
1))/(a*b*n*(p + 1)), x] - Dist[(a*d - b*c*(n*(p + 1) + 1))/(a*b*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /
; FreeQ[{a, b, c, d, n, p}, x] && NeQ[b*c - a*d, 0] && (LtQ[p, -1] || ILtQ[1/n + p, 0])

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rubi steps

\begin{align*} \int \frac{A+B x^2}{\left (a+b x^2\right )^2} \, dx &=\frac{(A b-a B) x}{2 a b \left (a+b x^2\right )}+\frac{(A b+a B) \int \frac{1}{a+b x^2} \, dx}{2 a b}\\ &=\frac{(A b-a B) x}{2 a b \left (a+b x^2\right )}+\frac{(A b+a B) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{2 a^{3/2} b^{3/2}}\\ \end{align*}

Mathematica [A]  time = 0.0435718, size = 63, normalized size = 1. \[ \frac{(a B+A b) \tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{a}}\right )}{2 a^{3/2} b^{3/2}}-\frac{x (a B-A b)}{2 a b \left (a+b x^2\right )} \]

Antiderivative was successfully verified.

[In]

Integrate[(A + B*x^2)/(a + b*x^2)^2,x]

[Out]

-((-(A*b) + a*B)*x)/(2*a*b*(a + b*x^2)) + ((A*b + a*B)*ArcTan[(Sqrt[b]*x)/Sqrt[a]])/(2*a^(3/2)*b^(3/2))

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Maple [A]  time = 0.007, size = 68, normalized size = 1.1 \begin{align*}{\frac{ \left ( Ab-Ba \right ) x}{2\,ab \left ( b{x}^{2}+a \right ) }}+{\frac{A}{2\,a}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}}+{\frac{B}{2\,b}\arctan \left ({bx{\frac{1}{\sqrt{ab}}}} \right ){\frac{1}{\sqrt{ab}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((B*x^2+A)/(b*x^2+a)^2,x)

[Out]

1/2*(A*b-B*a)*x/a/b/(b*x^2+a)+1/2/a/(a*b)^(1/2)*arctan(b*x/(a*b)^(1/2))*A+1/2/b/(a*b)^(1/2)*arctan(b*x/(a*b)^(
1/2))*B

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Maxima [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x^2+A)/(b*x^2+a)^2,x, algorithm="maxima")

[Out]

Exception raised: ValueError

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Fricas [A]  time = 1.32335, size = 381, normalized size = 6.05 \begin{align*} \left [-\frac{{\left (B a^{2} + A a b +{\left (B a b + A b^{2}\right )} x^{2}\right )} \sqrt{-a b} \log \left (\frac{b x^{2} - 2 \, \sqrt{-a b} x - a}{b x^{2} + a}\right ) + 2 \,{\left (B a^{2} b - A a b^{2}\right )} x}{4 \,{\left (a^{2} b^{3} x^{2} + a^{3} b^{2}\right )}}, \frac{{\left (B a^{2} + A a b +{\left (B a b + A b^{2}\right )} x^{2}\right )} \sqrt{a b} \arctan \left (\frac{\sqrt{a b} x}{a}\right ) -{\left (B a^{2} b - A a b^{2}\right )} x}{2 \,{\left (a^{2} b^{3} x^{2} + a^{3} b^{2}\right )}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x^2+A)/(b*x^2+a)^2,x, algorithm="fricas")

[Out]

[-1/4*((B*a^2 + A*a*b + (B*a*b + A*b^2)*x^2)*sqrt(-a*b)*log((b*x^2 - 2*sqrt(-a*b)*x - a)/(b*x^2 + a)) + 2*(B*a
^2*b - A*a*b^2)*x)/(a^2*b^3*x^2 + a^3*b^2), 1/2*((B*a^2 + A*a*b + (B*a*b + A*b^2)*x^2)*sqrt(a*b)*arctan(sqrt(a
*b)*x/a) - (B*a^2*b - A*a*b^2)*x)/(a^2*b^3*x^2 + a^3*b^2)]

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Sympy [B]  time = 0.542572, size = 112, normalized size = 1.78 \begin{align*} - \frac{x \left (- A b + B a\right )}{2 a^{2} b + 2 a b^{2} x^{2}} - \frac{\sqrt{- \frac{1}{a^{3} b^{3}}} \left (A b + B a\right ) \log{\left (- a^{2} b \sqrt{- \frac{1}{a^{3} b^{3}}} + x \right )}}{4} + \frac{\sqrt{- \frac{1}{a^{3} b^{3}}} \left (A b + B a\right ) \log{\left (a^{2} b \sqrt{- \frac{1}{a^{3} b^{3}}} + x \right )}}{4} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x**2+A)/(b*x**2+a)**2,x)

[Out]

-x*(-A*b + B*a)/(2*a**2*b + 2*a*b**2*x**2) - sqrt(-1/(a**3*b**3))*(A*b + B*a)*log(-a**2*b*sqrt(-1/(a**3*b**3))
+ x)/4 + sqrt(-1/(a**3*b**3))*(A*b + B*a)*log(a**2*b*sqrt(-1/(a**3*b**3)) + x)/4

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Giac [A]  time = 1.16405, size = 77, normalized size = 1.22 \begin{align*} \frac{{\left (B a + A b\right )} \arctan \left (\frac{b x}{\sqrt{a b}}\right )}{2 \, \sqrt{a b} a b} - \frac{B a x - A b x}{2 \,{\left (b x^{2} + a\right )} a b} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((B*x^2+A)/(b*x^2+a)^2,x, algorithm="giac")

[Out]

1/2*(B*a + A*b)*arctan(b*x/sqrt(a*b))/(sqrt(a*b)*a*b) - 1/2*(B*a*x - A*b*x)/((b*x^2 + a)*a*b)